-.25x^2+3.5x+2=0

Solution for -.25x^2+3.5x+2=0 equation:

-.25x^2+3.5x+2=0

We add all the numbers together, and all the variables

-0.25x^2+3.5x+2=0

a = -0.25; b = 3.5; c = +2;
Δ = b2-4ac
Δ = 3.52-4·(-0.25)·2
Δ = 14.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.5)-\sqrt{14.25}}{2*-0.25}=\frac{-3.5-\sqrt{14.25}}{-0.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.5)+\sqrt{14.25}}{2*-0.25}=\frac{-3.5+\sqrt{14.25}}{-0.5}
$